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 对称
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#include <iostream>
using namespace std;
int main() {
int n;
cin >> n;
int temp = n;
int rev = 0;
while (temp > 0) {
int digit = temp % 10;
rev = rev * 10 + digit;
temp /= 10;
}
if (rev == n) cout << "yes";
else cout << "no";
return 0;
}
( 2026/6/25 17:39:40 ) |
| 搞错了 |
#include <iostream>
using namespace std;
int main() {
int n;
cin>>n;
int temp=n;
int rev=0;
while (temp>0) {
int digit=temp%10;
rev=rev*10+digit;
temp/=10;
}
if(rev==n)cout<<"yes";
else cout << "no";
return 0;
}
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